IMO this is the only sound answer other than the accepted one. Free 30 Day Trial This multiple expression combinator is an efficient way to select disparate elements. Examples might be simplified to improve reading and basic understanding. #3 Use jQuery each function to iterate over a list element.. Answer: Use the jQuery each() Method You can simply use the jQuery each() method to loop through elements with the same class and perform some action based on the specific condition. Approach: Select the ID’s of different element and then use each() method to apply the CSS property on all selected ID’s element. From what I've seen in jQuery, it first checks to see if the selector is a simple id like If you have multiple elements with same id or same name, just assign same class to those multiple elements and access them by index & perform your required operation.Everybody says "Each id value must be used only once within a document", but what we do to get the elements we need when we have a stupid page that has more than one element with same id.
You can do this in 2 ways.

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To achieve selecting the other elements you can do something like thisYou will get a collection with all elements with id=duplicatedIdyou can simply write $('span#a').length to get the length.Thanks for contributing an answer to Stack Overflow! Description: Matches elements that match all of the specified attribute filters. Here in this example will loop over HTML element.i.e LI tag and display the text of li tag.Our HTML markup UL, Li tag as written below. Nice work! In jQuery, you could study the code to find out what any given version was doing, but since this is illegal HTML, there is no guarantee that it will stay the same over time. Tutorials, references, and examples are constantly reviewed to avoid errors, but we cannot warrant full correctness of all content. JQuery | Multiple ID selectors Last Updated: 28-06-2019. site design / logo © 2020 Stack Exchange Inc; user contributions licensed under The Overflow Blog The jQuery code in the following example will loop through each DIV elements and highlight the background of only those elements which are empty. COLOR PICKER. While using this site, you agree to have read and accepted our Stack Overflow works best with JavaScript enabled Featured on Meta By clicking “Post Your Answer”, you agree to our To subscribe to this RSS feed, copy and paste this URL into your RSS reader. He's getting it from Google, that's the problem@RalphLavelle - I added a method of dealing with dup IDs if you're stuck with it.You can try out this option jsfiddle.net/sx7jnh58/1 The example shows how to access the elementsThis doesn't answer the question about why multiple elements are returned with combination selectors.This doesn't answer the question about why multiple elements are returned with combination selectors.This doesn't answer the question about why multiple elements are returned with combination selectors.This doesn't answer the question about why multiple elements are returned with combination selectors. Using a loop. In simple way if you use id to select all div having same ids then it will select first id only but if you want to select ,want go through each div or any other element with same id then I will explain you how you can do that. Thanks to Justin Young for requesting this new function and getting me to do something useful ;). The loop is the simplest one conceptually. From the id Selector jQuery page: Each id value must be used only once within a document.
Required. Setting attribute values. version added: 1.0 jQuery( "[attributeFilter1][attributeFilter2][attributeFilterN]" ) attributeFilter1: An attribute filter. index - The index position of the selector; element - The current element (the "this" selector can also be used) jQuery Misc Methods. the idea is your delay function delays by that amount and accumulates the delay in each element's animation, so if your animations were each 500 miliseconds your delay values would be 500, 1000, 1500) edit: FYI jquery's 'slow' speed is also 600miliseconds. Inside [jQuery] Using each() for multiple $('table') elements - jQuery Forum I fetch data from Google's AdWords website which has multiple elements with the same Could you please explain why the following 3 queries doesn't result with the same answer (2)?Having 2 elements with the same ID is not valid html according to the W3C specification.When your CSS selector only has an ID selector (and is not used on a specific context), jQuery uses the native However, in the other two instances, jQuery relies on the Sizzle selector engine (or However, you should never have two elements on the same page with the same ID. One is using a loop, the other is using event bubbling. As before, the aim was to make portable, accessible code. But what about if you want to show/hide multiple elements independently? You can also use attr() to add attributes or change attribute values, as follows: If the attribute doesn’t exist in the element… The order of the DOM elements in the returned jQuery object may not be identical, as they will be in document order. (replace 1000 with your desired animation speed.

If we use JQuery '#duplicatedId' selector we get the first element only.

Hiding a single element with Jquery was pretty straightforward. A function to run for each matched element. – … If you need it for your CSS, use a class instead.If you absolutely must select by duplicate ID, use an attribute selector:There should only be one element with a given id. your coworkers to find and share information.